0=36q^2-q-100

Solution for 0=36q^2-q-100 equation:

0=36q^2-q-100

We move all terms to the left:

0-(36q^2-q-100)=0

We add all the numbers together, and all the variables

-(36q^2-q-100)=0

We get rid of parentheses

-36q^2+q+100=0

a = -36; b = 1; c = +100;
Δ = b2-4ac
Δ = 12-4·(-36)·100
Δ = 14401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{14401}}{2*-36}=\frac{-1-\sqrt{14401}}{-72}
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{14401}}{2*-36}=\frac{-1+\sqrt{14401}}{-72}
$